6x^2+5x-4/8x^2-10x+3

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Solution for 6x^2+5x-4/8x^2-10x+3 equation: 


x in (-oo:+oo)

6*x^2-((4/8)*x^2)+5*x-(10*x)+3 = 0

6*x^2+(-1/2)*x^2+5*x-10*x+3 = 0

11/2*x^2-5*x+3 = 0

DELTA = (-5)^2-(3*4*11/2)

DELTA = -41

DELTA < 0

x belongs to the empty set

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